chaycebell74021
25.04.2020 •
Chemistry
A sample of water with a mass of 622.7g undergoes a temperature change from 90.98°C
to 96.70°C. What is the heat change in Joules? Cwater=4.18J/g°C
A)0251608.10
B)3561.8J
C)14888.5)
D)2.51X105)
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Ответ:
C) Q = 14888.5 J
Explanation:
Q = mCΔT∴ m H2O = 622.7 g
∴ C H2O = 4.18 J/g°C
∴ ΔT= 96.7°C - 90.98°C = 5.72°C
⇒ Q = (622.7 g)(4.18 J/g°C)(5.72°C)
⇒ Q = 14888.508 J
Ответ: