jokerr5584
16.06.2020 •
Chemistry
A solution has [OH-] of 1x10^-2, what is the pOH of this solution
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Ответ:
The answer is: [D]: "12" .
Explanation:
i just did it
Ответ:
The question ought to be 'what is the change in free energy of the reaction' since the entropy was already given in the question and the formula for obtaining the free energy was specified.
-142.19KJ
Explanation:
From ∆G = ∆H - T∆S
∆H= -198KJ or -198000KJ
∆S= -187.9 JK-1
T= 297.0K
∆G= -198000-[297.0×(-187.9)]
∆G= -198000+55806.3
= -142193.7
=-142.19KJ