A solution is made by dissolving 1.12 g glucose (C6H12O6) in 104.0 g of water to give a final volume of 105 mL. Calculate the molarity, mass percent, mole fraction, and molality of glucose in this solution. What is the amount of C6H12O6 present in moles
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Ответ:
2 Cu2S + 3 O2 = 2 Cu2O + 2 SO2
Explanation:
2 Cu2S + 3 O2 = 2 Cu2O + 2 SO2