Chemistry: A vessel contains 18.06*10^23 molecules of Ammonia gas at 25oc. Calculate the number of atoms present

A vessel contains 18.06*10^23 molecules of Ammonia

Ответ:

ckfuentes6272

17.03.2022

$72.3\times 10^{23}$ atoms

Explanation:

According to avogadro's law, 1 mole of every substance contains avogadro's number $6.023\times 10^{23}$ of particles and weighs equal to the molecular mass.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given molecules}}{\text {avogadro's number}}$

$[tex]\text{Number of moles of ammonia}=\frac{18.06\times 10^{23}}{6.023\times 10^{23}}=3moles$

As 1 mole of NH_3 contains = $4\times 6.023\times 10^{23}$ atoms

3 moles of NH_3 contains = $\frac{4\times 6.023\times 10^{23}}{1}\times 3=72.3\times 10^{23}$ atoms

Thus $72.3\times 10^{23}$ atoms are present

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Ответ:

robertgib76

04.06.2022

Chemistry

Critical coordinate drivers incorporate living space alter, climate alter, obtrusive species, over exploitation, and contamination. Most of the coordinate drivers of corruption in biological systems and biodiversity right now stay steady or are developing in escalated in most biological systems.

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A vessel contains 18.06*10^23 molecules of Ammonia gas at 25oc. Calculate the number of atoms present

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