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raquelqueengucci25
25.07.2019 •
Chemistry
A20.0 ml sample of 0.150 m ethylamine is titrated with 0.050 m hcl. you may want to reference (page 805) section 17.4 while completing this problem. part a what is the ph after the addition of 5.0 ml of hcl? for ethylamine, pkb= 3.25.
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Ответ:
moles of ethylamine = molarity * volume
= 0.15 M * 0.02 L
= 0.003 mol
moles of H+ = molarity * volume
= 0.05 M * 0.005 L
= 0.00025 mol
when the total volume = 0.02 L + 0.005L
= 0.025 L
[H+] = moles / total volume
= 0.00025 / 0.025 = 0.01 M
[ethaylamine] = moles / total volume
= 0.003 / 0.025 = 0.12 M
when Pkb = 3.25 so we can get Pka from this formula:
Pka = 14 - Pkb
= 14 - 3.25
= 10.75
by using H-H equation:
PH = Pka + ㏒[salt]/[acid]
= 10.75 +㏒[0.12/0.01]
= 11.8
Ответ:
Water is the only polar compound so I guess that must be odd one out. I’m sorry I’m of no actual help.