A25.0-milliliter sample of hno3(aq) is neutralized by 32.1 milliliters of 0.150 m koh(aq). what is the molarity of the hno3(aq)?
(1) 0.117 m (3) 0.193 m
(2) 0.150 m (4) 0.300 m

The answer is (3) 0.193M. To find the molarity of HNO3, you just need to use the M1V1=M2V2 equation (no need to worry about ionization constants because HNO3 is monoprotic and KOH dissociates 1:1). Since the molarity you are looking for is M1, you get M1=M2V2/V1=(0.150)(32.1)/25.0= 0.193M

turen the pictureo sideways

Explanation: