amandavelez12122005
28.07.2019 •
Chemistry
A50.0-g sample of liquid water at 25.0 â°c is mixed with 23.0 g of water at 79.0 â°c. the final temperature of the water is â°c.
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Ответ:
m1ΔT1+m2ΔT2=0
m1(Tfl–lT∘1)+m2(Tfl–lT∘2)=0
50.0g×(Tfl–l25.0 °C)+23.0g×(Tfl–l57.0 °C)=0
50.0Tf−1250 °C+23.0Tf – 1311 °C=0
73.0Tf=2561 °C
Tf=2561 °C73.0=35.1 °C
Ответ:
i do
Explanation: