Chemistry: A581.2 ml sample of carbon dioxide was heated to 347 k. if the volume of the carbon dioxide sample at 347 k is 830.5 ml, what was its temperature at 581.2 ml?

A581.2 ml sample of carbon dioxide was heated to

Ответ:

connersitte1221l

12.01.2022

Chemistry

The temperature at 581.2 mL volume was 242.8 K.

Explanation:

Using Charle's law

$\frac {V_1}{T_1}=\frac {V_2}{T_2}$

Given ,

V₁ = 581.2 mL

V₂ = 830.5 mL

T₁ = ?

T₂ = 347 K

Using above equation as:

$\frac {581.2\ mL}{T_1}=\frac {830.5\ mL}{347\ K}$

$T_1=\frac{581.2\times 347}{830.5}\ K=242.8\ K$

The temperature at 581.2 mL volume was 242.8 K.

0,0(0 оценок)

Ответ:

monkeys450

06.03.2020

Chemistry

Explanation:

The agricultural and industrial sectors use the majority of fresh water. ... Increases in agricultural uses have benefited us because more food has been produced. Increases in industrial uses have benefited us because industries make the products that we use.

0,0(0 оценок)

A581.2 ml sample of carbon dioxide was heated to 347 k.

if the volume of the carbon dioxide sample at 347 k is 830.5 ml, what was its temperature at 581.2 ml?

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Chemistry

Ask an AI advisor a question