hpelir1282
18.11.2019 •
Chemistry
A988ml sample of air is at 852 mm hg and 34.1 c. what will the temperature of this gas be, in fahrenheit, at 955 mm hg and a volume of 602 ml
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Ответ:
T₂ = 63.78 °F
Explanation:
Given data:
Initial Volume = 988 mL
Initial Pressure = 852 mmHg
Initial temperature = 34.1 °C
Final pressure = 955 mmHg
Final volume = 602 mL
Final temperature = ?
Solution:
(34.1 °C × 9/5) +32 = 93.38 °F
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
T₂ = P₂V₂T₁/P₁V₁
T₂ = 955 mmHg × 602 mL × 93.38 °F / 852 mmHg× 988mL.
T₂ = 53685095.8 °F /841776
T₂ = 63.78 °F
Ответ:
2-chloro-1,3-dimethylcyclopentane
Explanation