According to the equation
HCl + NaOH → NaCl + H2O,
the total number of moles of HCl that can be
neutralized by 80 grams of NaOH is
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Ответ:
2 moles of HCl.
Explanation:
Given data:
Mass of NaOH = 80 g
Number of HCl neutralized by NaOH = ?
Solution:
Chemical equation:
NaOH + HCl NaCl + H₂O
Number of moles of NaOH:
Number of moles = mass/ molar mass
Number of moles = 80 g/ 40 g/mol
Number of moles = 2 mol
Now we will compare the moles of NaOH and HCl,
NaOH : HCl
1 : 1
2 : 2
Thus, 2 moles of HCl will neutralized by 80 gram of NaOH.
Ответ:
correct answer would be d