Chemistry: Acertain radioisotope has a half-life of 8.0 hours; how much of a 192 g sample of this radioisotope would decay after a full day?

Synthesis or a combination reaction. Two of the reactants form one final product in the end....

Acertain radioisotope has a half-life of 8.0 hours;

xolocsin

09.01.2022

167.9895 grams sample of this radioisotope would decay after a full day.

Explanation:

$N=N_o\times e^{-\lambda t}$

$\lambda =\frac{0.693}{t_{1/2}}$

N_o = initial amount of radioisotope

N = Amount of radioisotope left after time t.

$\lambda$ = Decay Constant

$t_{1/2}$ = Half life of the radioisotope

We have:

N_o=192 g

$t_{1/2}=8.0 hours$

t = 1 day = 24 hour

$\lambda =\frac{0.693}{8.0 hour}=0.086625 hour^{-1}$

$N=192 g\times e^{-0.086625 hour^{-1}\times 24 hours}$

N = 24.0105 g

24.0105 grams of radioisotope will remain after 1 whole day.

Amount of radioisotope decayed = N_o-N=192 g- 24.0105 g=167.9895 g

167.9895 grams sample of this radioisotope would decay after a full day.

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