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micahatwood03
28.07.2019 •
Chemistry
Achunk of lead at 91.6 c was added to 200.0g of water at 15.5 c. the specific heat of lead is 0.129j/g c. when the temperature stabilized, the temperature of the mixture was 17.9 c. assuming no heat was lost to the surroundings, what was the mass of lead added?
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Ответ:
Q for lead + Q for water = 0
So,
Q for lead = -Q for water
where
Q = mass*specific heat*(T₂ - T₁)
The specific heat of liquid water is 4.187 J/g·°C
Substituting the values:
(m)(0.129 J/g·°C)(17.9 - 91.6°C) = -(200 g)(4.187 J/g·°C)(17.9 - 15.5°C)
Solving for m,
m = 211.39 grams of lead
Ответ: