ekerns2000paa19x
27.09.2019 •
Chemistry
Agraduated cylinder contains 22.0 ml of water. what is the new water level after 34.0g of silver metal with a density of 10.5 g/ml is submerged in the water?
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Ответ:
v=m/d=34.0/10.5g/ml=3.24 ml 22.0+3.24=25.24 ml new level
Explanation:
Ответ: