Chemistry: Air in an internal combustion engine is at 440°f and 150 psia, with a volume of 10 in3 what is the mass of air (in lbm)?

DescriptionIn thermodynamics, the compressibility factor, also known as the compression factor or the gas deviation factor, is a correction factor which describes the deviation of a real gas from ideal gas behaviour....

Air in an internal combustion engine is at 440°f

Ответ:

wannaoneisforever

02.01.2022

Chemistry

The mass of air is 0.00260 lbs.

Explanation:

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

Or,

$PV=\frac{m}{M}RT$

where,

P = pressure of the gas = 150 psia = 10.2 atm (Conversion factor: 1 psia = 0.068 atm)

V = Volume of gas = 10in^3=0.164L (Conversion factor: 1in^3=0.0164L )

m = mass of air = ?

M = Average molar mass of air = 28.97 g/mol

R = Gas constant = $0.0820\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the gas = 440^oF=499.817K (Conversion factor: $(T(K)-273.15)=(T(^oF)-32)\times \frac{5}{9}$ )

Putting values in above equation, we get:

$10.2atm\times 0.164L=\frac{m}{28.97g/mol}\times 0.0820\text{ L atm }mol^{-1}K^{-1}\times 499.817K\\\\m=1.18g$

Converting this mass into lbs, we use the conversion factor:

1 lbs = 454 g

So, $1.18g\times \frac{1lbs}{454g}=0.00260lbs$

Hence, the mass of air is 0.00260 lbs.

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Air in an internal combustion engine is at 440°f and 150 psia, with a volume of 10 in3 what is the mass of air (in lbm)?

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