Among the following, which is an oxidation-reduction reaction? question 13 options: na2s + caco3 → cas + na2co3 2hno3 + mg(oh)2 → mg(no3)2 + 2h2o h2 + f2 → 2hf 3ba(oh)2 + 2h3po4 → ba3(po4)2 + 6h2o

This one is an oxidation-rdcution equation:

H2 + F2 → 2HF

How can you tell?

If the oxidation states of the atoms in the reactans are different from the oxidation states of the same atoms in the products then it is an oxidation-reduction reaction.

Both atoms H and F in the reactants have oxidation states 0.

That is a basic rule: any atom alone or bonded to the same kind of atom has oxidation state 0.

The oxidation states in HF are: H: +1, and F: -1.

So, the H increased its oxidation state, which is that ii is oxydized ; while F reduced its oxidation state so it is reduced.

H2 + F2 > 2HF

The molecules start to lose energy and slowly come together to form a regular pattern. At this point, they will have a small amount of energy and will not be moving as fast as before, as they are touching and can hardly move. Hope this is what you were looking For!