An experiment is supposed to test whether growth hormone affects the rate of growth in tomato plants. One group of plants is grown without any growth hormone. What is the purpose of this group of plants?

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Ответ:

PayeA6901

23.02.2022

Chemistry

We need 2.933 L of 0.15 mg /mL of protein solution.

Explanation:

Concentration of given solution C_1 = 0.15 mg/mL

1 mg = 0.001 g , 1 mL = 0.001 L

$C_1=\frac{0.15\times 0.001 mg}{1\times 0.001 L}=0.15 g/L$

Molecular weight of protein = 22,000 Da =22,000 g/mol

Initial concentration in moles/liter:

$C_1=\frac{0.15 g/L}{22,000 g/mol}=6.8182\times 10^{-6} mol/L$

Initial concentration in micromoles/mL :

1 L = 1000 mL

$C_1=6.8182\times 10^{-6} mol/L=\frac{6.8182\times 10^{-6}\times 10^6 \mu mol}{1000 mL}=6.8182\times 10^{-3} \mu mole/ mL$

Initial concentration in micromoles/microLiter :

1 L = 1000,000 μL

$C_1=6.8182\times 10^{-6} mol/L=\frac{6.8182\times 10^{-6}\times 10^6 \mu mol}{1000000 \mu L}=6.8182\times 10^{-6}\mu mol/\mu L$

Moles of protein required = 20 μmoles

n(Moles)=C(concentration) × V(Volume of solution)

$20 \mu mol=6.8182\times 10^{-6}\mu mol/\mu L\times V$

$V =\frac{20 \mu mol}{6.8182\times 10^{-6}\mu mol/\mu L}$

$V=2.933\times 10^6 \mu L = 2.933 L$

We need 2.933 L of 0.15 mg /mL of protein solution.

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