queenskmk9330
11.11.2020 •
Chemistry
An ideal gas had a mass of 0.0218g and occupied a volume of 1.111L at 0oC and 0.0100atm. What is the molar mass of this gas?
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Ответ:
Explanation:
we shall use gas law formula to solve the problem .
P = .01 atm
V = 1.111 L
T = 273 K
mass of gas = .0218
molar mass = M
no of moles n = .0218 / M
PV = n RT
.01 x 1.111 = (.0218 / M) x .082 x 273
.0218 / M = .000496
M = .0218 / .000496
= 43.95
Ответ:
thanks for the points
Explanation: