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tatedason33741
13.09.2019 •
Chemistry
An object weighing 10 grams is spinning in a centrifuge such that an acceleration of 13.0 g is imposed to it. the arm connecting the shaft to the object is r = 6.0 inches. if a = acceleration = rω2 where ω = angular speed in rad/s, determine:
mass of the object in lbm
rpm (revolutions per minute) of the shaft
force acting on the object in lbf
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Ответ:
1) 0.022 lbm
2) 276.253 RPM
3) 0.287 lbf
Explanation:
Given data:
mass = 10 kg
acceleration -![13 g = 13\times 9.81 m/s^2 = 12](/tpl/images/0230/3751/40ed3.png)
7.53 m/s^2
r =6 inches = 0.1524 m
1) mass in lbm![= 0.01\times 2.2 = 0.022 lbm](/tpl/images/0230/3751/bcf79.png)
as 1 kg = 2.2 lbm
2) acceleration![= r \omega ^2](/tpl/images/0230/3751/308e9.png)
SO IN![28.927 rad/s = \frac{60}{2\pi} \times 28.297 = 276.253 RPM](/tpl/images/0230/3751/80b02.png)
3) Force in![N = mass \times a = 0.01\times 127.53 = 1.2753 N](/tpl/images/0230/3751/12fc8.png)
Ответ: