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aaaranda0308
21.03.2021 •
Chemistry
An unknown amount of water
was heated with 3.5 kJ, raising
its temperature from 26°C to
66°C. What was the mass of
the water?
Solved
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Ответ:
20.9grams
Explanation:
Using the formula:
Q = m × c × ∆T
Where;
Q = amount of heat (joules)
m = mass of substance (g)
c = specific heat of water (4.184 J/g°C)
∆T = change in temperature (°C)
According to the provided information;
Q = 3.5kJ = 3.5 × 1000 = 3500J
m = ?
c of water = 4.184 J/g°C
∆T = 66°C - 26°C = 40°C
Using Q = m × c × ∆T
m = Q ÷ (c × ∆T)
m = 3500 ÷ (4.184 × 40)
m = 3500 ÷ 167.36
m = 20.9
mass = 20.9grams
Ответ:
Given information:
Mass of pure silver = 195 mg
To determine :
Mass of silver chloride required to plate 195 mg of pure silver
Calculation:
The silver chloride used for silver plating usually contains 75.27 % silver
i.e.
every 100 mg of silver chloride will contain 75.27 mg silver
therefore, amount of silver chloride corresponding to 195 mg of silver would be = 195 mg * 100 mg/75.27 mg
= 259.1 mg