Ariellelyn176

13.03.2021 •

Chemistry

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Ответ:

shanilafaridor97hl

21.02.2023

Chemistry

The equations are given below.

Explanation:

For the given options:

Option 1:

The molecular equation for this follows:

$AgNO_3(aq.)+NaI(aq.)\rightarrow AgI(s)+NaNO_3(aq.)$

Ionic form of the above equation follows:

$Ag^+(aq.)+NO_3^-(aq.)+Na^+(aq.)+I^-(aq.)\rightarrow AgI(s)+Na^+(aq.)+NO_3^-(aq.)$

As, sodium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation.

The net ionic equation for the above reaction follows:

$Ag^+(aq.)+I^-(aq.)\rightarrow AgI(s)$

Option 2:

The molecular equation for this follows:

$Ba(NO_3)_2(aq.)+K_2SO_4(aq.)\rightarrow 2KNO_3(aq.)+BaSO_4(s)$

Ionic form of the above equation follows:

$Ba^{2+}(aq.)+2NO_3^-(aq.)+K^+(aq.)+SO_4^{2-}(aq.)\rightarrow 2K^+(aq.)+2NO_3^-(aq.)+BaSO_4(s)$

As, potassium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation.

The net ionic equation for the above reaction follows:

$Ba^{2+}(aq.)+SO_4^{2-}(aq.)\rightarrow BaSO_4(s)$

Option 3:

The molecular equation for this follows:

$2NH_4NO_3(aq.)+K_2SO_4(aq.)\rightarrow 2KNO_3(aq.)+H_2SO_4(aq.)+NH_3(g)$

Ionic form of the above equation follows:

$2NH_4^+(aq.)+2NO_3^-(aq.)+2K^+(aq.)+SO_4^{2-}(aq.)\rightarrow 2NH_3(g)+2H^+(aq.)+SO_4^{2-}(aq.)+2K^+(aq.)+2NO_3^-(aq.)$

As, nitrate, potassium and sulfate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation.

The net ionic equation for the above reaction follows:

$2NH_4^+(aq.)\rightarrow 2NH_3(g)+2H^+(aq.)$

Option 4:

The molecular equation for this follows:

$3LiCl(aq.)+Al(NO_3)_3(aq.)\rightarrow 3LiNO_3(aq.)+AlCl_3(s)$

Ionic form of the above equation follows:

$3Li^+(aq.)+3Cl^-(aq.)+Al^{3+}(aq.)+NO_3^-(aq.)\rightarrow 3Li^+(aq.)+3NO_3^-(aq.)+AlCl_3(s)$

As, lithium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation.

The net ionic equation for the above reaction follows:

$Al^{3+}(aq.)+3Cl^-(aq.)\rightarrow AlCl_3(s)$

Hence, the molecular and ionic equations are given above.

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