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stichgotrich849
23.01.2020 •
Chemistry
Apharmacy intern is asked to prepare 3 l of a 30% w/v solution. t he pharmacy stocks the active ingredient in 8-ounce bottles of 70% w/v strength. how many bottles will be needed as the source of the active ingredient?
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Ответ:
The number of bottles that will be needed are 6
Explanation:
We are given:
Amount of solution, the intern is asked to prepare = 3 L = 3000 mL (Conversion factor: 1 L = 1000 mL)
Strength of solution needed = 30 % (w/v)
This means that in 100 mL of solution, the solute present is 30 grams
So, in 3000 mL of solution, the solute present will be =![\frac{30}{100}\times 3000=900g](/tpl/images/0467/8302/3693c.png)
Active ingredient present in 1 bottle = 8 ounce of 70 % (w/v)
Conversion factor used: 1 ounce = 29.57 mL
So,![8ounce\times \frac{29.57mL}{1ounce}=236.6mL](/tpl/images/0467/8302/90110.png)
Amount of active ingredient present in 1 bottle =![236.6\times \frac{70}{100}=165.6g](/tpl/images/0467/8302/4fc4d.png)
To calculate the number of bottles, we need to divide the total amount of solution needed by the amount of active ingredient present in 1 bottle, we get:
Putting values in above equation, we get:
Hence, the number of bottles that will be needed are 6
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