Aqueous solutions of sodium sulfide and copper(II) chloride are mixed together. Which statement is correct? a.Both NaCl and CuS will precipitate from solution b.No precipitate will form c.Only CuS will precipitate from solution d.Only NaCl will precipitate from solution

C.Only CuS will precipitate from solution

Aqueous solutions of sodium sulfide and copper(II) chloride are mixed together.

Na₂S(aq) + CuCl₂(aq) → Products

Na₂S(aq) + CuCl₂(aq) →  CuS(s) ↓ +  2NaCl(aq)

When the sulfide bond to the cation Cu²⁺ it makes a precipitate (s)

Thus,the correct answer is C.

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The correct state for the answer is c.

Only CuS will precipitate from solution

Explanation:

We analyse the compounds for the reaction and we write the equation:

Na₂S(aq) + CuCl₂(aq) → Products

For this case, the products are NaCl and CuS. The complete balanced reaction is:

Na₂S(aq) + CuCl₂(aq) →  CuS(s) ↓ +  2NaCl(aq)

When the sulfide bond to the cation Cu²⁺ it makes a precipitate (s)

Salts from chlorides are soluble except for the Ag⁺, Pb⁺ or Cu⁺

Salts from S⁻² which are soluble, are found in the group 2 of the Periodic Table (Ca²⁺, Ba²⁺, Mg²⁺)

The correct state for the answer is c.

Explanation:

s