Asample of compressed methane has a volume of 648 ml at a pressure of 503 kpa. to what pressure would the methane have to be compressed in order to have a volume of 216 ml?

 To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1 =P2V2

P2 = P1 x V1 / V2

P2 = 503 x 648 / 216

P2 =1509 kPa

it has to be 2%