Asample of water at 0 ºc has a mass of 10 grams. how much energy is absorbed when this sample melts?

This should help :)

Example #1: A 36.0 g sample of water is initially at 10.0 °C. How much energy is required to turn it into steam at 200.0 °C? (This example starts with a temperature change, then a phase change followed by another temperature change.)

Solution:

q = (36.0 g) (90.0 °C) (4.184 J g¯1 °C¯1) = 13,556 J = 13.556 kJ q = (40.7 kJ/mol) (36.0 g / 18.0 g/mol) = 81.4 kJ q = (36.0 g) (100.0 °C) (2.02 J g¯1 °C¯1) = 7272 J = 7.272 kJ q = 102 kJ (rounded to the appropriate number of significant figures)

1.) J

2.) C - arrows hitting each other

3.) A - W & X

4.) D, i think

Explanation: