Asaturated solution of lead(ii) chloride, pbcl2, was prepared by dissolving solid pbcl2 in water. the concentration of pb2+ ion in the solution was found to be 1.62×10−2 m . calculate ksp for pbcl2.
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Ответ:
Ksp for PbCl2 is 1.7 *10^-5
Explanation:
Step 1: Data given
The concentration of Pb2+ ion in the solution was found to be 1.62 *10^−2 M
Step 2: The balanced equation
PbCl2 ⇔Pb^2+ +2Cl -
Step 2: ICE chart
The initial concentration of Pb2+ is 0 M
There will react X M and 2X of Cl-
At the equillibrium there is X M of Pb^2+ and 2X M of Cl-
The concentration of Pb2+ ion in the solution was found to be 1.62 *10^−2 M
Step 3: Calculate Ksp
Since PbCl2 is solid, it doesn't aply for Ksp
Ksp = [Pb^2+][Cl-]²
Ksp = X*(2X)²
Ksp = 4X³
⇒ X = 1.62 *10^-2 M
Ksp = 4*( 1.62 *10^-2)³
Ksp =1.7 *10^-5
Ksp for PbCl2 is 1.7 *10^-5
Ответ:
the way a plant or any other living organism moves as an reaction to light. there are 2 types of reactions, which is either towards light (positive phototropism) or away from the light (negative phototropism).
Explanation: