Chemistry: Asolution is prepared by dissolving 31.9 g cesium chloride in 60.0 g water. the volume of the solution is 63.3 ml. calculate the molality of the cscl solution.

Asolution is prepared by dissolving 31.9 g cesium

hayleighsmall111

02.01.2022

The molality of the CsCl solution is 3.2 m.

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

$Molality=\frac{n\times 1000}{W_s}$

where,

n = moles of solute

moles of solute = $\frac{\text {given mass}}{\text {molar mass}}=\frac{31.9g}{168.36g/mol}=0.19moles$

Now put all the given values in the formula of molarity, we get

W_s = weight of solvent (water) in g = 60.0 g

Molality = $\frac{0.19\times 1000}{60}=3.2mol/kg$

Thus molality of the CsCl solution is 3.2 m.

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yyy77uh

28.02.2023

19kpa

Explanation:

The total pressure of a mixture of gases is the sum of the partial pressure exacted by the individual gases.

P total = P X + P Y

From the question above:

P total = P .nitrogen + P. oxygen

123.5kpa = 104.5kpa + P. Oxygen

P. Oxygen = 123.5kpa - 104.5kpa

= 19kpa

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