Nathaliasmiles
06.07.2019 •
Chemistry
Astock solution of na3c16h9n4o9s2 (tartrazine, or yellow no. 5) was prepared by placing 0.035- g in a 500 ml volumetric flask and diluting to 500 ml with distilled water. what is the molar concentration?
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Ответ:
molar mass of tartrazine = (3 mol Na)(23 g Na/1 mol Na) + (16 mol C)(12 g C/1 mol C) + (9 mol H)(1 g H/1 mol H) + (9 mol O)(16 g O/1 mol O) + (2 mol S)(32 g S/1 mol S) = 478 g/mol
Then, determine the number of moles of the substance by dividing the given mass by the calculated molar mass.
n = (0.035 g)(1 mol tartrazine / 478 g tartrazine)
= 7.32 x 10⁻⁵ mol of tartrazine
Then, divide the calculated number of moles by the volume of the solvent in L which will be equal to 0.5 L.
M = (7.32 x 10⁻⁵ mol of tartrazine / 0.5 L) = 1.46 x 10⁻⁴ M tartrazine
ANSWER: 1.46 x 10⁻⁴ M tartrazine
Ответ:
Letter D.
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