Chemistry: Astrip of copper 370 μm thick and 4.5 mm wide is placed in a uniform magnetic field b with arrow of magnitude 0.30 t, with b with arrow perpendicular to the strip. a current i = 24 a is then sent through the strip such that a hall potential difference v appears across the width of the strip. calculate v. (the number of charge carriers per unit volume for copper is 8.47 ✕ 1028 electrons/m3.)

Astrip of copper 370 μm thick and 4.5 mm wide is

dayi80

07.01.2022

Explanation:

The given data is as follows.

Magnetic field (B) = 0.30 T

Current (I) = 24 A

n = $370 \times 10^{-6} m$

charge on electron (e) = $1.602 \times 10^{-19}$ C

Formula to calculate the potential difference is as follows.

V = $\frac{B \times I/d}{n \times e
}$

= $\frac{0.30 T \times 24 amps}{8.47 \times 10^{28} electrons/ m^{3} \times 370 \times 10^{-6} m \times 1.602 \times 10^{-19} C)}$

= $1.38 \times 10^{-6}$ V

Therefore, we can conclude that value of potential difference is $1.38 \times 10^{-6}$ V.

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pettismayersjoy3le8

03.09.2022

If you are in no rush, I recommend reading this website to find more on the uniqueness of carbon-

https://www.infoplease.com/math-science/chemistry/the-chemistry-of-biology-organic-chemistry

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