Chemistry: Astudent collects 285 ml of o2 gas at a temperature of 15°c and a pressure of 0.983 atm. the next day, the same sample occupies 292 ml at a temperature of 11°c. what is the new pressure of the gas? 0.946 atm 1.00 atm 0.704 atm

Astudent collects 285 ml of o2 gas at a temperature

Ответ:

abhibhambhani

12.03.2022

Chemistry

0.946 atm

Explanation:-

From the question we see,

First day pressure P 1 = 0.983 atm

First day temperature T 1 =15 C + 273 = 288 K

First day volume V 1 =285 mL

Second Day volume V 2 = 292 mL

Second day Temperature T 2 = 11 C + 273 = 284 K

Using the relation

P 1 V 1 / T 1 = P 2 V 2 / T 2

We get Second Pressure P 2 = P 1 V 1 T 2 / ( T 1 V 2)

= 0.983 atm x 285 mL x 284 K / ( 288 K x 292 mL)

= 0.946 atm

Hence the new pressure of the gas on the second day is 0.946 atm

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Ответ:

coolfreekid3

12.03.2022

Chemistry

According to the combined gas laws,

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

$P_{1} = 0.983 atm$

$V_{1}=285 mL$

$T_{1} = 15^{0} + 273 = 288 K$

$P_{2} = ?$

$V_{2}=292 mL$

$T_{2} = 11^{0} + 273 = 284 K$

Plugging in the values and solving for the final pressure:

$\frac{0.983 atm(285 mL)}{288 K} = \frac{P_{2}(292 mL)}{284 K}$

Final pressure $P_{2} = 0.946 atm$

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Ответ:

ob3ymysins

13.12.2021

Chemistry

It is A.

Explanation:

stop trying to get people to wrte an essay for you

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Astudent collects 285 ml of o2 gas at a temperature of 15°c and a pressure of 0.983 atm. the next day, the same sample occupies 292 ml at a temperature of 11°c. what is the new pressure of the gas? 0.946 atm 1.00 atm 0.704 atm

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