Astudent weighs out 0.477 g of khp (molar mass = 204.22 g/mol) and titrates to the equivalence point with 36.78 ml of a stock naoh solution. what is the concentration of the stock naoh solution? khp is an acid with one acidic proton.

Number of moles of KOH = mass/molar mass
number of moles of KOH = 0.477/204.22 = 2.3357x10^-3 moles

Now, number of moles of NaOH is equal to the number of moles of KOH, this means that:
number of moles of NaOH = 2.3357x10^-3 moles

molarity can be calculated using the following rule:
molarity = number of moles of solute/liters of solution
molarity of NaOH = (2.3357x10^-3) / ( 0.03678) = 0.0635 molar

Based on this, stock of NaOH = 0.0635 molar

= 14.63 × particles.

Explanation:

According to Avogadro's priciple:

1 mole of any substance is 6.02 × particles

∴ 2.43 x moles × 6.02 ×

= 14.63 × particles.

I hope this was clear and easy to understand.