Asubstance contains 36.1 percent calcium and 63.9 percent chlorine by weight. what is the empirical formula of thegiven compound?

Assume 100 g of the compound is present. This converts the percentages into mass. Then, calculate moles of each element: 

Ca ---> 36.1 g / 40.08 g/mol = 0.9007 
Cl ---> 63.9 g / 35.453 g/mol = 1.802 

Next, look for the lowest whole-number ratio. We do this by dividing by the smallest value: 

Ca ---> 0.9007 / 0.9007 = 1 
Cl ---> 1.802 / 0.9007 = 2 

The empirical formula is CaCl2 

To go from moles to grams, molar mass needs to be used as a conversion factor.  The Periodic Table tells you the molar mass of silver.  Mine says it's 107.9 g/mol.  Start the unit analysis with the given data and then multiply by the conversion factor:

Notice that units of moles is in the denominator to allow us to cancel out the moles.

Taking significant figures into account, the mass for 88.624 moles of silver is 9562.5 grams.  However, since we are rounding to the nearest whole number, the answer is simply 9562 grams.

9562 grams