At 298 k, the henry's law constant for oxygen is 0.00130 m/atm. air is 21.0% oxygen. at 298 k, what is the solubility of oxygen in water exposed to air at 1.00 atm?
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Ответ:
amu In = 114.818 amu
Explanation:
Indium (In):
∴ 95.7% 115In
∴ 4.3% 113In
∴ atomic mass 113In = 112.904 amu
∴ atomic mass 115In = 114.904 amu
average atomic mass (In):
⇒ amu In = (0.957)(114.904 amu) + (0.043)(112.902 amu)
⇒ amu In = 109.963 amu + 4.855 amu
⇒ amu In = 114.818 amu