At a certain temperature, 0.660 mol SO 3 is placed in a 4.00 L container. 2 SO 3 ( g ) − ⇀ ↽ − 2 SO 2 ( g ) + O 2 ( g ) At equilibrium, 0.110 mol O 2 is present. Calculate K c .

Explanation:

Hello,

In this case, for the given chemical reaction at equilibrium:

The initial concentration of sulfur trioxide is:

Hence, the law of mass action to compute Kc results:

In such a way, in terms of the change due to the reaction extent, by using the ICE method, it is modified as:

In that case, as at equilibrium 0.11 moles of oxygen are present, equals:

Therefore, the equilibrium constant finally turns out:

Best regards.

When sugar is added to water, water molecules surround the each sugar molecules separating it and dissolving it into solution.

when you add a pebble to water the water will surround the pebble but won't breaks up the pebbles molecules and dissolve it.

That the main difference

Hope that helps