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fernandaElizondo
23.03.2020 •
Chemistry
At a pressure of 780.0 mmHg and 25.2 C, a certain gas has a volume of 350.0 mL. What will be the volume of this gas under STP
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Ответ:
The volume will be 0,330 L (330 ml).
Explanation:
We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T. The conditions STP are 1 atm of pressure and 273 K of temperature. We convert the unit Celsius into Kelvin, the volume in ml into L and the pressure in mmHg into atm:
0 ° C = 273K, 25,2= 273 + 25, 2= 298,2K ; 350/1000= 0,350 L
760 mmHg1 atm
780 mmHgx= (780 mmHgx 1 atm)/760 mmHg=1, 03 atm
P1xV1/T1= P2xV2/T2
V2 =((P1xV1/T1)xT2)/P2
V2=((1, 03 atmx 0,350 L/298,2K)x273K)/1 atm= 0,330 L
Ответ:
An addition polymer is a polymer which is formed by an addition reaction, where many monomers bond together via rearrangement of bonds without the loss of any atom or molecule under specific condition of heat, pressure, catalyst.
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