Atmospheric pressure on the peak of Mt. Everest can be as low as 150 mm Hg, which is why climbers need to bring oxygen tanks for the last part of
the climb. If the climbers carry 10.0 liter tanks with an internal gas
pressure of 30400 mm Hg, what will be the volume of the gas when it is
released from the tanks?

Volume of gas when release form tank = V₂ = 2026.67 L

Explanation:

Given data:

Initial volume of gas =V₁= 10.0 L

Pressure of gas inside tank =P₁= 30400 mmHg

Volume of gas when release form tank =V₂=  ?

Pressure at peak =P₂= 150 mmHg

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

30400 mmHg × 10.0 L =  150 mmHg × V₂

V₂ = 304000 mmHg. L/  150 mmHg

V₂ = 2026.67 L

So, only one electron is there with n = 0, l = 0 and its quantum set is n = 0, l = 0, ml = 0, ms = -1/2. Hope, this is helping. The maximum number of electrons that can fit inside a 'n' shell is 2n^2. So it would be 1.

Explanation: