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Bamaboy8804
03.12.2020 •
Chemistry
Balance the following equations:
i. H2SO4 + ….NaHCO3 → Na2SO4 + ….H2O + ……CO2
ii. H2 + I2 → ….HI
iii. …..NaOH + H2SO4 → Na2SO4 + …..H2O
iv. ……FeSO4 → Fe2O3 + SO2 + SO3
v. C3H6O2 + …..O2 → ….CO2 + …..H2O
b) Calculate the molecular masses of the following:
i. H2SO4
ii. CH4
iii. NH3
c) 56g of iron reacts with 71g of chlorine. How many grams of iron react with 35.5g of chlorine?
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Ответ:
(I)![H_2SO_4+ 2NaHCO_3-- Na_2SO_4 + 2 H_2O + 2CO_2](/tpl/images/0945/3909/99f7b.png)
(II)![H_2+I_2 -- 2HI](/tpl/images/0945/3909/38395.png)
(III)![2NaOH+H_2SO_4-- Na_2SO_4+ 2H_2O](/tpl/images/0945/3909/39e64.png)
(IV)![2FeSO_4-- Fe_2O_3+SO_2+SO_3](/tpl/images/0945/3909/f7265.png)
(V)![2C_3H_6O_2+7O_2--6CO_2+6H_2O](/tpl/images/0945/3909/5c06d.png)
_____________________________________Molecular Masses of the following:------------------------------------------------------------------------------------------------------------
(I)![H_2SO_4](/tpl/images/0945/3909/c48b6.png)
(ANS)![98 \frac{grams}{mol}](/tpl/images/0945/3909/61011.png)
__________________________________________________________
Solution:
Molecular mass of,
H = 1
S = 32
O = 16
Now,
There are 2 atoms of Hydrogen, 1 atoms of Sulfur and 4 atoms of Oxygen present, thus,
![H_2SO_4 = 98 \frac{grams}{mol}](/tpl/images/0945/3909/8fd37.png)
_____________________________________(II)![CH_4](/tpl/images/0945/3909/bef5d.png)
(ANS)![16 \frac{gram}{mol}](/tpl/images/0945/3909/94e92.png)
_________________________________________________________
Solution:
Molecular Mass,
Carbon = 12
Hydrogen = 1
Now
There are 1 atom of Oxygen and 4 atoms of Hydrogen present, thus,
![CH_4 = 16\frac{grams}{mol}](/tpl/images/0945/3909/9ebca.png)
_____________________________________(III)![NH_3](/tpl/images/0945/3909/b033f.png)
(ANS)![17 \frac{grams}{mol}](/tpl/images/0945/3909/cb8a7.png)
__________________________________________________________
Solution:
Molecular Mass,
Nitrogen = 14 grams
Hydrogen = 1
Now,
There are 1 atoms of Nitrogen and 3 atoms of Hydrogen present, thus,
![NH_3 = 17 \frac{grams}{mol}](/tpl/images/0945/3909/a9b41.png)
_____________________________________How many Grams of Iron(fe):56 71
x 35.5
_____________________________________Simplify the equation
X = 28 grams
__________________________________________________________
28 grams of Iron(fe) will react with chlorine.
_____________________________________Best Regards,'Borz'Ответ:
A. Four C–H single bonds and two O=O double bonds.
Explanation:
The chemical reaction proceeds with breaking bonds in the reacting molecules and forming new bonds in the products.In this reaction four single bonds are broken in CH₄ and two double bonds O=O are broken in two molecules of O₂.Also, two double bonds C=O are formed in CO₂ molecules and 4 single bonds O–H are formed in 2 molecules of H₂O (each molecule contain 2 new bonds).So, A is the right answer.