Based on the acid strength of H2SO3 and H2SeO3, will the equilibrium constant of H2SO3(aq)+HSeO3−(aq)⇌H2SeO3(aq)+HSO3−(aq) be (Kc> 1) or (Kc< 1)? Group of answer choices Kc< 1, because H2SO3 is a stronger acid than H2SeO3 Kc< 1, because H2SO3 is a weaker acid than H2SeO3 Kc> 1, because H2SO3 is a weaker acid than H2SeO3 Kc> 1, because H2SO3 is a stronger acid than H2SeO3
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Ответ:
Kc> 1, because is a stronger acid than
Explanation:
We have to start analyzing the reaction:
When we search the pKa values for each we will find:
pKa of = 1.81
pKa of = 2.62
When we have a smallest pKa value we will have more acidity, therefore is a stronger acid than . Additionally, if we have his behavior the reaction would be displaced to the right side due to the strong acid (the strong acid is placed in the reactives side), so we will have a K greater than 1.
The answers are:
a) Kc< 1, because is a stronger acid than
b) Kc< 1, because is a weaker acid than
c) Kc> 1, because is a weaker acid than
d) Kc> 1, because is a stronger acid than
The answer that fits with the previous analysis is "d". The molecule is the strongest acid and K is greater than one
Ответ:
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