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deannabrown2293
16.03.2020 •
Chemistry
CaCl₂(s) → Ca²⁺(aq) + 2Cl⁻(aq) ∆H = -81.5 kJ/mol A 15.0-g sample of CaCl₂ is dissolved in 105 g water with both substances at 25.0°C. Calculate the final temperature of the solution assuming no heat loss to the surroundings and assuming the solution has a specific heat capacity of 4.18 J/°C・g.
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Ответ:
The final temperature of the solution is 46.93°C
Explanation:
we have to calculate the heat produced.
where,
q = heat released = ?
m = mass of CaCl_2 = 15.0 g
Molar mass of CaCl_2 = 110.98 g/mol
Now put all the given values in the above formula, we get:
calculate the final temperature of solution in the calorimeter.
where,
q = heat produced = 11.0 kJ = 11000 J
m = mass of solution = 15.0 + 105 = 120.0 g
c = specific heat capacity of water = 4.18J/g°C
Now put all the given values in the above formula, we get:
The final temperature of the solution is 46.93°C
Ответ:
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