Calcium carbonate decomposes at high temperatures to form carbon dioxide and calcium oxide. How many grams of calcium carbonate will I need to form 3.45 L of CO2? CaCO3(s) --> CO2 (g) + Cao (s)

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Ответ:

Angeldelissa

21.02.2020

Chemistry

1.1 mol H₂O

General Formulas and Concepts:

Chemistry

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Dimensional Analysis

Explanation:

Step 1: Define

6.8 × 10²³ molecules H₂O

Step 2: Convert

$6.8 \cdot 10^{23} \ mc \ H_2O(\frac{1 \ mol \ H_2O}{6.022 \cdot 10^{23} \ mc \ H_2O} )$ = 1.12919 mol H₂O

Step 3: Check

We are given 2 sig figs. Follow sig fig rules.

1.12919 mol H₂O ≈ 1.1 mol H₂O

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Calcium carbonate decomposes at high temperatures to form carbon dioxide and calcium oxide. How many grams of calcium carbonate will I need to form 3.45 L of CO2? CaCO3(s) --> CO2 (g) + Cao (s) ​