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sherlinejules1
03.11.2020 •
Chemistry
Calcuate the number of
grams of solute in 453.9mL
of 0.237 M calcium acetate
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Ответ:
The number of grams : 17.082 g
Further explanationMolarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
453.9 mL of 0.237 M calcium acetate
mol![\tt mol=M\times V=0.237\times 0.4539=0.108](/tpl/images/0862/8816/b9755.png)
massMW Ca(C₂H₃OO)₂ : 158,17 g/mol
Ответ:
Circuit breaker.
Explanation: