Calculate ΔS°rxn (J/k) for 3NO2(g) + H2O(l)LaTeX:

Ответ:

ineedhelpplz40

21.01.2022

$\Delta _RS=-287.6J/K$

$\Delta _RS=972.4J/K$

Explanation:

Hello,

In this case, the entropy of reaction is computed via:

$\Delta _RS=\Sigma\nu_i S_i^0_{product}-\Sigma\nu_i S_i^0_{reactant}$

In such a way, for the given reactions, we find:

- 3NO2(g) + H2O(l) ⟶ NO(g) +2HNO3(l)

$\Delta _RS=2*146+210.65-69.940-3*239.9=-287.6J/K$

- C6H12O6(s) + 6O2(g) LaTeX: \longrightarrow⟶ 6H2O(g) +6CO2(g)

$\Delta _RS=6*188.72+6*213.7-212.1-6*205.0=972.4J/K$

Best regards.

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