Calculate the amount of cuso4•5h2o required to make 25 ml of a 0.45 m solution of cuso4.

Mass = 1.76 g

Explanation:

Given data:

Volume of solution = 25 mL

Molarity = 0.45 M

Amount of CuSO₄.5H₂O = ?

Solution:

Molarity = number of moles / volume in litter

Number of moles = Molarity × Volume in L

Number of moles = 0.45 M  × 0.025 L

Number of moles = 0.011 mol

Mass of f CuSO₄.5H₂O:

Mass = Number of moles ×  molar mass

Mass = 0.011 mol × 159.6 g/mol

Mass = 1.76 g

The CH₃ carbon atom has tetrahedral geometry and the nitrile carbon atom has linear geometry

Explanation:

According to VSEPR theory, in an acetonitrile:

The outer carbon atom CH₃, which is connected to three hydrogen atoms and one central carbon atom, has 4 bond pairs of electrons and zero lone pair. Therefore, outer carbon atom CH₃ has a TETRAHEDRAL geometry.

The nitrile carbon atom (C≡N), which forms a single bond with the outer CH₃ carbon atom and triple bond with the nitrogen atom, has two bond pairs and zero lone pairs.

Therefore, nitrile carbon atom has a LINEAR geometry.