Calculate the binding energy per nucleon for a 157N715N nucleus. The mass of the neutral atom of 157N715N is 15.000109 uu, the mass of the neutral atom of 11H11H is 1.007825 uu and the mass of neutron is 1.008665
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Ответ:
The binding energy per nucleon for a
nucleus is 7.7 MeV. It was calculated with the mass of the neutral atom
(15.000109 u), the mass of proton ¹H (1.007825 u), and the mass of neutron (1.008665 u).
We can calculate the binding energy per nucleon with the following equation:
Where:
c: is the speed of light
A: is the number of nucleons in the nucleus of
= 15
We know that 1 u = 931.5 MeV/c², so the binding energy is:
Where:
p: is the number of protons = 7
n: is the number of neutrons = A - p = 15 - 7 = 8
By entering the above values into equation (1), we have:
Therefore, the binding energy per nucleon is 7.7 MeV.
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Ответ:
Explanation:
The binding energy of a nucleus is given by
where
Here the mass of the nucleus is
While the mass of the nucleons is:
The nucleus
containes 7 protons (atomic number) and 15 nucleons (mass number), which means that the number of neutrons is
So the mass defect is:
1 atomic mass unit is
So the mass defect in kilograms is
Finally, we can use eq(1) to find the binding energy:
Ответ:
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