Calculate the energy in joules to heat 171 g of
mercury from 37.0◦ C to 42.0◦ C. The specific
heat capacity of Hg(ℓ) is 0.139 J/g· ◦C.
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Ответ:
Explanation:
There is 575.46 J of heat released
Explanation:
Step 1: Data given
Mass of mercury = 828 grams
Heat capacity of mercury = 0.139J/g°C
Initial temperature = 37.0°C
Final temperature = 42.0 °C
Step 2: Calculate heat released
Q = m*c*ΔT
⇒ Q =the heat released in Joule
⇒ m = the mass of mercury = 828 grams
⇒ c = the heat capacity of mercury = 0.139 J/g°C
⇒ ΔT = the change of temperature = T2 - T1 = 42.0 - 37.0 = 5.0 °C
Q = 828 g * 0.139 J/g°C * 5.0 °C
Q = 575.46 J
There is 575.46 J of heat released
Ответ: