rosepederson80
22.04.2020 •
Chemistry
Calculate the free energy δg at 25 ∘c for the nonstandard conditions at point c where the reaction quotient q is 3.58×109.
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Ответ:
∆G=13.68kj
Explanation:
Free energy=?
Quotient q=3.58*10^9
Also ∆G signs-40.8
T=25°c ie 298°c.
Using this formula
∆Gf=∆G+RTinq
We're R =8.314= 0.008314kj
∆Gf= -40.8+0.008314*298in3.58*20^9
∆Gf=13.68kj
Ответ:
there is nun there
Explanation: