Calculate the freezing point of a solution containing 25 grams of kcl and 2750.0 grams of water. the molal freezing point depression constant (kf) for water is 1.86 ∘c/m.1.23 oc-0.45 oc+0.45 oc-0.23 oc+0.23 oc

-0.45 °C

Explanation:

The freezing point depression can be calculated using the formula:

Where ΔT is the change of the freezing point temperature (from 0°C of pure water), Kf is 1.86 °C/m, b is the molality, and i is 2 (in this case with KCl).

All data required is given except for b, so we calculate the molality:

25 g KCl ÷ 74.55g/mol = 0.3353 mol KCl

2750 g water ⇒ 2750/1000 = 2.75 kg water

Now we calculate ΔT:

So the freezing point of the solution is [0°C - 0.45°C] = -0.45 °C