Calculate the mass in grams of iodine (i2) that will react completely with 27.1 g of aluminum (al) to form aluminum iodide (ali3).

The equation of reaction is
I                  +              Al>  AlI3
1 mol                                              1mol
n mol                                              n mole
so nI =nAll3

nAll3=mAll3/M= 27.5g/27+3x127=0.067mol

and then  nI=0.067mol = mI/MI
from where we can get  mI=nIxMI=0.067x 127=8.56g

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