Calculate the mass of sodium acetate trihydrate required to make 100. ml of a 0.100 m solution. as part of your preparation for performing this experiment, record your answer to this question in your lab notebook so that you have it ready to use during the lab session. if you do not get this question correct, make sure to revisit the calculation and check your corrected value with your ta prior to preparing the solution in lab.

Required moles of CH₃COONa.3H₂O = Molarity x Volume of solution in L

                                                            = 0.100 M x (100.0 mL)

                                                            = 0.100 M x 0.100 L

                                                            = 0.01 mol

Required mass of CH₃COONa.3H₂O = Required moles x Molar mass

                                                            = 0.01 mol x (136.08 g / mol)                                                                              = 1.3608 g

So, if you are given the mass of an element, you use the periodic table to find its molar mass, and multiply the given mass by the reciprocal of the molar mass. This is Mass → Moles . Once you have moles, multiply by Avogadro's number to calculate the number of atoms. This is Moles → Atoms .

Explanation: