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taliyahjhonson1
28.08.2019 •
Chemistry
Calculate the molality of a 25.4% (by mass) aqueous solution of phosphoric acid (h3po4).
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Ответ:
The molality of a 25.4 % (by mass) aqueous solution of phosphoric acid
is
.
Further Explanation:
The proportion of substance in the mixture is called concentration. The most commonly used concentration terms are as follows:
1. Molarity (M)
2. Molality (m)
3. Mole fraction (X)
4. Parts per million (ppm)
5. Mass percent ((w/w) %)
6. Volume percent ((v/v) %)
Molality is equal to the amount of solute that is dissolved in one kilogram of the solvent. It is denoted by m and its unit is moles per kilograms (mol/kg). The component present in smaller quantity is solute while that in larger quantity is known as a solvent. The solute gets itself dissolved in the solvent.
The formula to calculate the molality of
solution is as follows:
Consider 100 g to be the mass of the sample. Phosphoric acid
is 25.4 % by mass. So the mass of
is 25.4 g.
The formula to calculate the mass of
solution is as follows:
Rearrange equation (2) to calculate the mass of
.
The mass of
solution is 100 g.
The mass of
is 25.4 g.
Substitute these values in equation (3).
Mass of
is to be converted into kg. The conversion factor for this is,
So the mass of
is calculated as follows:
The formula to calculate the moles of
is as follows:
Substitute 25.4 g for the given mass and 97.99 g/mol for the molar mass of
in equation (4).
Substitute 0.2592 mol for the amount of
and 0.0746 kg for the mass of
in equation (1).
Therefore the molality of
solution is 3.47 m.
Learn more:
1. What is the concentration of alcohol in terms of molarity?
2. What is the molarity of the stock solution?:
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Solutions
Keywords: concentration terms, molality, m, mol/kg, H3PO4, moles of H3PO4, mass of H2O, H2O, 25.4 %, 25.4 g, 100 g, 74.6 g, 0.2592 mol, 3.47 m.
Ответ:
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