Calculate the moles of 12.354 grams of c6h12o6

The correct answer is 0.06857 moles.

C₆H₁₂O₆, that is, glucose has six carbons, twelve hydrogens, and six oxygen atoms. The atomic weight of C, H and O are as follows:

Six atoms of carbon = 6 × 12.01 g = 72.06 g

Twelve atoms of hydrogen = 12 × 1.008 g = 12.096 g

Six atoms of oxygen = 6 × 16.00 g = 96.00 g

So, the molar mass of C₆H₁₂O₆ is 72.06 g + 12.096 g + 96.0 g = 180.156 g.

It can also be written in the form as 180.16 g of C₆H₁₂O₆ is equal to 1 mole of C₆H₁₂O₆or 180.16 g/mole (as the molar mass)

Now, there is a need to find moles of 12.354 grams of C₆H₁₂O₆. So, the final conversion is:

12.354 g C₆H₁₂O₆ × 1 mole of C₆H₁₂O₆ / 180.16 g C₆H₁₂O₆

= 0.06857 moles

d = 9.08 Kg/m³

Radon concentrations are greater in the basement.

Explanation:

To find the density of radon, we need to use the ideal gas law:

(1)

where, P: pressure, V: volume, n: moles of gas, T: absolute temperature y R: ideal gas constant.

Knowing that the number of moles is:

 (2)  

where m: mass of gas, and M: molar mass of gas,

Then, we can replace the number of moles into equation (1):

The density of the gas is giving by:

 (3)        

where: m: mass and V: volume of gas

Now, we can calculate the density of Radon:

The ²²²Rn is produced by the decay of radium isotope ²²⁶Ra from the uranium-238 decay chain. Uranium is present in ground minerals, from which the radon gas can emerge and then accumulate in basements of buildings, due to its high density. Hence, because of its high density compared to the air (about 1.225 Kg/m³), radon concentrations are likely to be greater in the basement than on the top floor of a building.